-1.2x^2+7x+7=0

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Solution for -1.2x^2+7x+7=0 equation:



-1.2x^2+7x+7=0
a = -1.2; b = 7; c = +7;
Δ = b2-4ac
Δ = 72-4·(-1.2)·7
Δ = 82.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{82.6}}{2*-1.2}=\frac{-7-\sqrt{82.6}}{-2.4} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{82.6}}{2*-1.2}=\frac{-7+\sqrt{82.6}}{-2.4} $

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